2x^2+20x-68=10

Solution for 2x^2+20x-68=10 equation:

Simplifying
2x2 + 20x + -68 = 10

Reorder the terms:
-68 + 20x + 2x2 = 10

Solving
-68 + 20x + 2x2 = 10

Solving for variable 'x'.

Reorder the terms:
-68 + -10 + 20x + 2x2 = 10 + -10

Combine like terms: -68 + -10 = -78
-78 + 20x + 2x2 = 10 + -10

Combine like terms: 10 + -10 = 0
-78 + 20x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-39 + 10x + x2) = 0

Factor a trinomial.
2((-13 + -1x)(3 + -1x)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(-13 + -1x)' equal to zero and attempt to solve:

Simplifying
-13 + -1x = 0

Solving
-13 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '13' to each side of the equation.
-13 + 13 + -1x = 0 + 13

Combine like terms: -13 + 13 = 0
0 + -1x = 0 + 13
-1x = 0 + 13

Combine like terms: 0 + 13 = 13
-1x = 13

Divide each side by '-1'.
x = -13

Simplifying
x = -13
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Solution
x = {-13, 3}